x^2(x-3)-2x(x-3)+(x-3)=0

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Solution for x^2(x-3)-2x(x-3)+(x-3)=0 equation: 


Simplifying
x2(x + -3) + -2x(x + -3) + (x + -3) = 0

Reorder the terms:
x2(-3 + x) + -2x(x + -3) + (x + -3) = 0
(-3 * x2 + x * x2) + -2x(x + -3) + (x + -3) = 0
(-3x2 + x3) + -2x(x + -3) + (x + -3) = 0

Reorder the terms:
-3x2 + x3 + -2x(-3 + x) + (x + -3) = 0
-3x2 + x3 + (-3 * -2x + x * -2x) + (x + -3) = 0
-3x2 + x3 + (6x + -2x2) + (x + -3) = 0

Reorder the terms:
-3x2 + x3 + 6x + -2x2 + (-3 + x) = 0

Remove parenthesis around (-3 + x)
-3x2 + x3 + 6x + -2x2 + -3 + x = 0

Reorder the terms:
-3 + 6x + x + -3x2 + -2x2 + x3 = 0

Combine like terms: 6x + x = 7x
-3 + 7x + -3x2 + -2x2 + x3 = 0

Combine like terms: -3x2 + -2x2 = -5x2
-3 + 7x + -5x2 + x3 = 0

Solving
-3 + 7x + -5x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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